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10 February, 19:33

How many moles of NaOH are present in 13.0 mL of 0.220 M NaOH?

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  1. 10 February, 19:57
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    V=13.0 mL=0.0130 L

    c=0.220 mol/L

    n=vc

    n=0.0130*0.220=0.00286=2.86*10⁻³ mol
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