What volume 12.6 M HCL must be added to enough water to prepare 5.00 litters of 3.00 M HCL?

To solve this problem, we shall use the role;

M1V1 = M2V2

M1: is the molarity of the solution before dilution.

V1: is the volume of the solution that we need to dilute.

M2: is the molarity of the solution after dilution.

V2: is the volume of the solution after dilution.

By substitution;

12*V1 = 3*5

V1 = 1.25 litters.