How many moles of butane gas, C4H10, react to produce 2.50 moles of H2O? How many moles of oxygen gas reacts? Given the balanced equation is, 2C4H10+13O2 = 8CO2+10H2O

Question

Chemistry

Noelle Browning

18 April, 07:23

How many moles of butane gas, C4H10, react to produce 2.50 moles of H2O? How many moles of oxygen gas reacts? Given the balanced equation is, 2C4H10+13O2 = 8CO2+10H2O

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Dude · Answer 1

The moles of butane gas and oxygen gas reacted if 2.50 moles of H2O is produced is calculated as below

the equation for reaction

2C4H10 + 13 O2 = 8CO2 + 10 H2O

the moles of butane (C4H10) reacted calculation

by use of mole ratio between C4H10: H2O which is 2 : 10 the moles of C4H10 = 2.50 x2/10 = 0.5 moles of C4H10 reacted

The moles of O2 reacted calculation

by use of mole ratio between O2 : H2O which is 13:10 the moles of O2

= 2.50 x 13/10 = 3.25 moles of O2 reacted