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31 August, 16:20

How much water must be added to 12.0 mL of 1.65 M LiCl to dilute the solution to 0.495 M LiCl?

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  1. 31 August, 19:30
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    To solve this problem, we use the formula:

    M1 V1 = M2 V2

    To calculate for the total final volume V2:

    V2 = M1 V1 / M2

    V2 = 1.65 M * 12 mL / 0.495 M

    V2 = 40 mL

    Since final volume is 40 mL so water needed is:

    water volume = 40 mL - 12 mL

    water volume = 28 mL
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