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6 May, 06:03

A jar containing only nickels and dimes contains a total of 60 coins. the value of all the coins in the jar is $4.45. solve by elimination to find the amount of nickels and dimes that are in the jar.

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  1. 6 May, 06:39
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    1 nickle = 5 cents

    1 dime = 10 cents

    $4.45 = 445 cents

    let

    n = the number of nickles, n>=0

    d = the number of dimes, d>=0

    a jar containing only nickels and dimes contain a total of 60 coins:

    n + d = 60

    the value of all the coins in the jar is $4.45:

    5n + 10d = 445

    by solving the system of equations:

    n + d = 60

    5n + 10d = 445

    we find:

    n = 31 nickels

    d = 29 dimes
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