The concentration of pb2 + in a commercially available standard solution is 1.00 mg/ml. what volume of this solution should be diluted to 6.0*102 ml to produce a solution in which the concentration of pb2 + is 0.054 mg/l?

The concentration of pb2 + = 1.00mg/ml Diluted Solution is 6.0 x 102 ml = 612 ml Volume of the concentration of pb2 + is 0.054 mg/l is v (vL) (1.00mg/ml) = (.612L) (0.054mg/l) Volume = 0.033048L Volume of the concentration of pb2 + is 0.054 mg/l = 33.048 ml.