What is the solubility of m (oh) 2 in a 0.202 m solution of m (no3) 2? ksp = 9.05*10-18?

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Chemistry

Leyla Gallegos

23 October, 23:56

What is the solubility of m (oh) 2 in a 0.202 m solution of m (no3) 2? ksp = 9.05*10-18?

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Andreas Coffey · Answer 1

M (NO3) 2 = = > [M2+] + 2 [NO3-] 0.202 M = = > 0.202 M M (OH) 2 = = > [M2+] + 2[OH-] 5.05*10^-18 = = = > s + [2s]^2 5.05*10^-18 = = = > 0.202 + [2s]^2 5.05*10^-18 = 0.202 * 4s^2 4s^2 = 25*10^-18 s^2 = 6.25*10^-18 s = 2.5*10^-9 So, the solubility is 2.5*10^-9