A container holds 35.8 moles of gas under 10.0 atm of pressure at 70.0 C. What is the volume of the container? 20.6 L 101 L 2080 L 10200 L

PV = n RT

P: pressure = 10atm

V volume

n number of mole = 35.8 moles

R universal gas constant = 0.082

T: The temperature = 70°C = 343.15 Kelvin

V = (n RT) / P = 35.8 x 0.082 x 343.15 / 10 = 100.7 ≈ 101 L

V = 101L