How many grams of magnesium chloride can be produced if we react 32.50 g Mg with 32.50 g HCl

The mass of magnesium chloride produced is calculated as follows

write the equation for reaction

Mg + 2HCl=MgCl + H2

find the moles of each reactant

moles = mass/molar mass

moles for mass = 32.5 g/24.3 g/mol = 1.34 moles

moles for HCl = 32.5g / 95.3 g/mol=0.89 moles

HCl is the limiting reagent hence by use of mole ratio between HCl to MgCl2 which is 2:1 the moles of MgCl2 is therefore = 0.89/2 = 0.445 moles

mass of MgCl2 is therefore = moles/molar mass

=0.445moles x 95.3 g/mol = 42.4 grams of MgCl2