A gas has a volume of 111 ml at a temperature of 32°c. What volume will the gas occupy at standard temperature?

From Charle's law the volume of a fixed mass of a gas is directly proportional to the absolute temperature at constant pressure.

Therefore V = kT where k is a constant

V1/T1=V2/T2

For standard conditions the temperature is 0 degrees celcius;

Thus; V1 = 111 ml, T1 = 32 + 273 = 305 K, V2 = ? T2 = 273

Hence; 111/305=V2 / 273

V2 = (111 * 273) / 305

= 99.354 ml