Ask Question
30 November, 06:55

If 29.50 ml of 0.175m nitric acid neutralizes 50.0 ml of ammonium hydroxide, what is the molarity of the base?

+2
Answers (1)
  1. 30 November, 09:59
    0
    The molarity of the base (ammonium hydroxide) is calculated as follows

    find the moles of Nitric acid = molarity x volume

    =29.5 x 0.175 = 5.163 moles of nitric acid

    write the equation for reaction

    HNO3 + NH4OH = NH4NO3 + H2O

    by use of mole ratio between HNO3 to NH4NO3 which is 1:1 the moles of NH4OH is also 5.163 moles

    molarity = moles/volume

    = 5.163 / 50=0.103 M is the molarity of the base
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “If 29.50 ml of 0.175m nitric acid neutralizes 50.0 ml of ammonium hydroxide, what is the molarity of the base? ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers