An aqueous solution is prepared by mixing 0.2750 moles of naoh (40.00 g mol-1) with 189.0 g of water. its density is 1.065 g ml-1. the solute is completely dissociated. what is the percent by weight of naoh in the solution?

Question

Chemistry

Kason Baxter

19 July, 00:14

An aqueous solution is prepared by mixing 0.2750 moles of naoh (40.00 g mol-1) with 189.0 g of water. its density is 1.065 g ml-1. the solute is completely dissociated. what is the percent by weight of naoh in the solution?

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Kristina Roy · Answer 1

The weight of NaoH=moles of NaOH where

Molar mass = 0.2750*40=11g

Mass of solution = (189+11) = 200g

So mass in pertcentage of NaoH = (11/200) * 100=5.5%