A particular experiment requires 13.5 µl hydrochloric acid solution. if 250 ml hydrochloric acid solution is available, how many times can the experiment be performed

The amount of HCl required for one experiment - 13.5 µl

the volume in terms of L - 13.5 x 10⁻⁶ L

the volume of HCl available - 0.250 L

since one experiment uses up - 13.5 x 10⁻⁶ L

then number of experiments - 0.250 L / 13.5 x 10⁻⁶ L = 1.8 x 10⁴ times

the experiment can be carried out 18000 times