How many moles of each reactant are needed to produce 3.60 x 10^2g ch3oh

Methanol is prepared by reacting Carbon monoxide and Hydrogen gas,

CO + 2 H₂ → CH₃OH

Calculating Moles of CO:

According to equation,

32 g (1 mole) of CH₃OH is produced by = 1 Mole of CO

So,

3.60 * 10² g of CH₃OH is produced by = X Moles of CO

Solving for X,

X = (3.60 * 10² g * 1 Mole) : 32 g

X = 11.25 Moles of CO

Calculating Moles of H₂:

According to equation,

32 g (1 mole) of CH₃OH is produced by = 2 Mole of H₂

So,

3.60 * 10² g of CH₃OH is produced by = X Moles of H₂

Solving for X,

X = (3.60 * 10² g * 2 Mole) : 32 g

X = 22.5 Moles of H₂

Result:

3.60 * 10² g of CH₃OH is produced by reacting 11.25 Moles of CO and 22.5 Moles of H₂.