What is the empirical formula of a compound consisting of 29.6% oxygen and 70.4% fluorine by mass?

O1Fl2

1. Assume an 100g sample, so the percentage will stay the same

2. Covert each element into their molar mass

29.6/16.00=1.8 mols of O

70.4/19.00=3.7 mols of Fl

3. Divide both by the smallest value of mol

1.8/1.8=1 O

3.7/1.8=2 Fl

4. Write the empirical formula:

O1Fl2