An air mass of volume 6.5 x 10 to the fifth L starts at sea level, where the pressure is 775 mm HG. It rises up a mountain where the pressure is 622 mm HG. Assuming no change in temperature, what is the volume of the air mass?

From Boyle's law the volume of a fixed mass of a gas is inversely proportional to temperature at constant absolute temperature.

Thus, Vα1/P

= V = k/P where k is a constant

P1V1=P2V2

Therefore; V2 = P1V1/P2

= (6.0 * 10^-5 * 775) / 622

= 7.476 * 10^-5 L

Hence, the new volume of the air mass is 7.476 * 10^-5 L