What is the molarity (m) of a solution prepared by dissolving 15.0 grams of na3po4 in enough water to make 250.0 ml of solution?

Molarity is the concentration of a solution expressed as the number of moles of solute in a liter of solution.

1 mole of NaPO4 contains 118 g;

Therefore 15 g is equivalent to (15/118) = 0.127 Moles

Thus, the molarity will be 0.127 * 1000/250 = 0.508 m

Hence the molarity will be 0.508 m