Ask Question
10 June, 01:07

Calcium fluoride (CaF2) has a solubility constant of 3.45 x 10-11

. What is the molar solubility of CaF2 in water?

4.15 x 10-6 M

5.87 x 10-6 M

2.05 x 10-4 M

3.26 x 10-4 M

+1
Answers (1)
  1. 10 June, 02:09
    0
    Ksp=3.45*10⁻¹¹

    CaF₂ (s) ⇄ Ca²⁺ (aq) + 2F⁻ (aq)

    Ksp=[Ca²⁺][F⁻]²

    [Ca²⁺]=C (CaF₂)

    [F⁻]=2C (CaF₂)

    Ksp=4{C (CaF₂) }³

    C (CaF₂) = ∛ (Ksp/4)

    C (CaF₂) = ∛ (3.45*10⁻¹¹/4) = 2.05*10⁻⁴ mol/L

    2.05*10⁻⁴ M
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Calcium fluoride (CaF2) has a solubility constant of 3.45 x 10-11 . What is the molar solubility of CaF2 in water? 4.15 x 10-6 M 5.87 x ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers