An ideal gas has a density of 1.10*10-6 g/cm3 at 1.00*10-3 atm and 80.0 ∘c. identify the gas.

From ideal gas equation that is pv = nRt

n=number of moles which can be written as the ratio between the weight of a gas that is mass and its molecular mass n=m/Mm

pv = (m/Mm) RT

density is=mass per unit volume

P=m/v by arranging the equation we get

R = 0.082atm/mol/k

Mm=pRT/P=[ (1.10 x10^-6 x1000g/l) xo. 082 atm/mol/k x (80+273] / (1.00 x10^-3) = 31.84 to the nearest ten is 32

hence the gas is oxygen