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15 May, 02:56

For hydrocyanic acid, HCN, Ka = 4.9 * 10-10. Calculate the pH of 0.20 M NaCN. What is the concentration of HCN in the solution? for the ph i got 10 is that right?

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  1. 15 May, 03:35
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    By using the ICE table:

    initial 0.2 M 0 0

    change - X + X + X

    Equ (0.2 - X) X X

    when Ka = (X) (X) / (0.2-X)

    so by substitution:

    4.9x10^-10 = X^2 / (0.2-X) by solving this equation for X

    ∴X ≈ 10^-6

    ∴[HCN] = 10^-6

    and PH = - ㏒[H+]

    = - ㏒ 10^-6

    = 6
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