If 38.7 grams of lithium chlorate decomposes, how many grams of oxygen gas can be produced?

2LiClO3 → 2LiCl + 3O2

41.1 g O2

20.6 g O2

9.13 g O2

6.85 g O2

Question

Chemistry

Lucille Shelton

11 January, 00:52

If 38.7 grams of lithium chlorate decomposes, how many grams of oxygen gas can be produced?

2LiClO3 → 2LiCl + 3O2

41.1 g O2

20.6 g O2

9.13 g O2

6.85 g O2

+5

Answers (2)

Know the Answer?

Tyrone Norris · Answer 1

LiClO3 has mole of mass of 90 g/mol

So 38.7 g means 0.43 mol

Since in this reaction, LiClO3 : O2 = 2:3, then it will produce 0.43*3/2 = 0.645 mol O2

So it is equivalent to 0.645 * 32 = 20.64 g O2

Leonidas Payne · Answer 2

The answer to your question is 20.6

If 38.7 grams of lithium chlorate decomposes, how many grams of oxygen gas can be produced?2LiClO3 → 2LiCl + 3O241.1 g O220.6 g O29.13 g O26.85 g O2

If 38.7 grams of lithium chlorate decomposes, how many grams of oxygen gas can be produced?

2LiClO3 → 2LiCl + 3O2

41.1 g O2

20.6 g O2

9.13 g O2

6.85 g O2