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4 January, 03:57

What is the empirical formula of a compound that is 56.95% cu, 14.37% s, and 28.68% o?

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  1. 4 January, 06:56
    0
    Assume 100g

    Cu = 56.95/63.5 = 0,89685

    S = 14.37/32 = 0.44906

    O = 28.68/16 = 1.7925

    Divide by the smallest

    2:1:4

    Therefore the formula is cu2so4
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