If he (g) has an average kinetic energy of 8750 j/mol under certain conditions, what is the root mean square speed of cl2 (g) molecules under the same conditions?

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Chemistry

Tess Holmes

2 February, 05:37

If he (g) has an average kinetic energy of 8750 j/mol under certain conditions, what is the root mean square speed of cl2 (g) molecules under the same conditions?

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Lainey Lopez · Answer 1

The root mean square speed is given by V_rms = âšRT/M where r, t, and m are the rate constant, temperature and molar mass the gas Average molar kinetic energy of the gas E = 1/2 M * (V_rms) ^2 = 8750 ms/1 So (V_rms) ^2 = (2 * 8750) / M Molar mass of 2 chlorine atoms in kg is 2 * 35 * 10^ (-3) Hence we have (V_rms) ^2 = (2 * 8750) / (2 * 35 * 10^ (-3)) (V_rms) ^2 = 8750/0.035 = 250000 So V_rms = âš 250000 = 500