How much energy does it take to convert. 500 kg of ice at - 20°C to steam at 250°C.

Specific heat capacities:

Ice: 2.03 J/g °C

Water: 4.2 J/g°C

Steam: 2.0 J/g C

Use the specific heat equation for each one:

Q = mCT

m is mass

T is change in temp

C is spec heat

You will not only have to calculate three different specific heats, but also do the heat of vaporization and heat of fusion.

Heat of vaporization is 3.33 * 10^5 J/Kg

Heat of Fusion is 2.26 * 10^6 J/Kg

You’ll want to make sure all your units match. So change all Kg to g (or g to Kg)

-20 to 0 = mC (Ice) T

Melt ice (fusion) = m (heat of fusion)

0 to 100 = mC (Water) T

Boil (Vaporization) = m (heat of vaporization)

100 to 250 = mC (Steam) T

Then add each one together