What volume of 0.100 m sodium chloride must be added to 75.0 ml of 0.200 m lead (ii) nitrate to precipitate all of the lead ions?

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Chemistry

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2 October, 11:50

What volume of 0.100 m sodium chloride must be added to 75.0 ml of 0.200 m lead (ii) nitrate to precipitate all of the lead ions?

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Shayna Blanchard · Answer 1

Reaction for precipitation is

Pb (NO3) 2 (aq) + 2Nacl (aq) →PbCL2 (s) + 2NaNO3 (aq)

The given reaction is

The mol of Nacl required is = 2*mol of Pb (NO3) 2 which is present.

∴M (Nacl) * V (Nacl) = 2*M (Pb (NO3) 2 * V (Pb (NO3) 2

o. 100M*V (Nacl) = 2*0.200 MX75.0ML

V (Nacl = 300mL.