What is the molarity of a solution made by dissolving 29.5 g of sodium hydroxide (NaOH) in enough water to make 2.45 L of solution?

Molar Mass Na: 22.99 g/mol

Molar Mass O: 16.00 g/mol

Molar Mass H: 1.008 g/mol

molarity is defined as the number of moles of solute in 1 L of solution.

the number of moles of NaOH = mass present / molar mass of NaOH

molar mass of NaOH = 22.99 + 16.00 + 1.008 = 40.00 g/mol

therefore NaOH moles = 29.5 g / 40.00 g/mol = 0.738 mol

the number of NaOH moles in 2.45 L solution - 0.738 mol

therefore number of NaOH moles in 1 L = 0.738 mol / 2.45 L = 0.301 mol/L molarity of NaOH = 0.301 M