Iron has a density of 7.87 g/cm3. How much does 1 cubic feet of iron weigh?

The answer would be 222853.216 grams

One foot equal to 30.48 centimeter which means for cubic feet it will be:

(30.48cm/ft) ^3 = 28316.8 cm^3/ft^3

Then, the weight of the iron would be:

weight = volume * density

weight = 1 ft^3 * (28316.8 cm^3/ft^3) * 7.87 g/cm3 = 222853.216 grams = 222.9 kg