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9 May, 03:11

How many moles of 0.225 M CaOH2 are present in 0.350 L of solution? Calculate the number of moles of solute (CaOH2) (M CaOH2) (0.350 L) = mol CaOH2

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  1. 9 May, 05:33
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    C=0.225 mol/L

    v=0.350 L

    n{Ca (OH) ₂}=cv

    n{Ca (OH) ₂}=0.225*0.350=0.07875 = 7.875*10⁻² mol
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