If i combined 15.0 grams of calcium hydroxide with 75.0 ml of 0.500 m hcl, how many grams of calcium chloride would be formed?

The equation is:

Ca (OH) ₂ (s) + 2 HCl (aq) → CaCl₂ (aq) + 2 H₂ O (l)

n=mass in g/M. M

15 g Ca (OH) ₂ is n=15 g / 74.1 g/mol=0.2024 mol of Ca (OH) ₂

no. of mol of HCl:

n=0.5 mol/L*0.075L=0.0375 mol

This could react with 0.0375/2 = 0.01875 mol of Ca (OH) ₂ We have a lot more than that.

Therefore, HCl is the limiting reagent and determines how much CaCl₂ forms.

Based on the balanced reaction, 2 moles of HCl gives 1 mole of CaCl₂

no. of mol of CaCl₂ = 0.0375/2 = 0.01875 mol

mass in g=n*MM = 0.01875*111 = 2.08 g