How many grams of N are in 89.0 g of NH4NO3

Step 1; calculate the molar mass of NH4N03

molar mass of different element

N=14

H=1

O=16

therefore molar mass of NH4NO3 is 14+4+14+48 = 80g/mol

step 2:find the molar mass of N present in NH4NO3

That is 14+14 = 28g/mol

the mass is therefore

{ (28g/mol/80g/mol) x 89g} = 31.15g