How many molecules of o2 are required to form 13.5 g of water vapor?

Question

Chemistry

Jolly

26 October, 19:13

How many molecules of o2 are required to form 13.5 g of water vapor?

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Answers (1)

Know the Answer?

Donte Reeves · Answer 1

13.5g H2O = 13.5 / (2+16) = 0.75 mol H2O

Since for every O2 you can form 2 H2O, 0.75/2 = 0.375 mol of O2 will be needed to form 0.75 mol of H2O.

Converting from moles to molecules:

0.375 mol * 6.022 * 10^23 = 2.26 * 10 ^23 molecules