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18 July, 18:25

How many moles of NaCl are required to prepare 2.90 L of 1.8 M NaCl?

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  1. 18 July, 21:02
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    How many moles of NaCl are required to prepare 2.90 L of 1.8 M NaCl?

    moles = molarity / liters or mol = M/L

    mol NaCl = 1.8 M / 2.90 L=0.62 mol NaCl
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