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30 October, 18:44

Ab2 has a molar solubility of 3.72*10-4 m. what is the value of the solubility product constant for ab2? express your answer numerically.

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  1. 30 October, 21:32
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    Answer is: Ksp for AB₂ is 2.06·10⁻¹⁰.

    Chemical reaction: AB ₂ (s) → Aˣ⁺ (aq) + 2Bⁿ⁻ (aq).

    s (AB ₂) = 3,72·10⁻⁴ M.

    s (AB ₂) = s (Aˣ⁺).

    s (Bⁿ⁻) = 2s (AB₂).

    Ksp (AB₂) = s (Aˣ⁺) · (s (Bⁿ⁻)) ².

    Ksp (AB₂) = 3,72·10⁻⁴ · (7,44·10⁻⁴) ².

    Ksp (AB₂) = 2,06·10⁻¹⁰.
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