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15 October, 02:10

How many liters of h2 would be formed at 600 mm hg and 13 ∘c if 26.5 g of zinc was allowed to react?

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  1. 15 October, 05:03
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    The number of liters of H2 that would be formed at 600 mmhg and 13 c if 26.5 g zinc was allowed to react is calculated as follows

    find the moles of Zn reacted

    that is 26.5 g / 56.39 g/mol = 0.4699 moles

    write the reaction Zn with an acid example HCl to produce H2

    that is Zn + 2 HCl = ZnCl2 + H2

    by use of mole ratio between Zn to H2 the moles of H2 = 0.4699 moles

    By use of Ideal gas equation Volume of H2 = nRT/P

    n = 0.499 moles

    R = 62.364 L. mmhg/mol. K

    T=13 + 273=286 k

    P = 600 mmhg

    = (0.4699 mol x 62.364 L. mmhg/mol. k x286 k) / 600 mm hg = 13.97 liters of H2
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