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16 March, 07:43

Calculate the mole fraction of solvent for a sucrose solution contains 20.0 g of sucrose (molar mass 342.3 g/mol) dissolved in 100.0 g of water at 25oc.

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  1. 16 March, 09:14
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    Mole fraction = moles of desired compound / total moles

    moles = mass (g) / molar mass (g/mol)

    Mass of sucrose = 20.0 g

    Moles of sucrose = 20.0 g / 342.3 g/mol = 0.058 mol

    Mass of water = 100.0 g

    Molar mass of water = 18 g/mol

    Moles of water = 100.0 g / 18 g/mol = 5.556 mol

    Total moles = moles of sucrose + moles of water

    = 0.058 mol + 5.556 mol

    = 5.614 mol

    Mole fraction of sucrose = moles of sucrose / total number of moles

    = 0.058 mol / 5.614 mol

    = 0.010
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