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7 April, 17:43

A 75.0 l steel tank at 20.0°c contains acetylene gas, c2h2, at a pressure of 1.39 atm. assuming ideal behavior, how many grams of acetylene are in the tank?

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  1. 7 April, 20:56
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    we can use the ideal gas law equation to find the number of moles of acetylene gas in the tank

    PV = nRT

    where

    P - pressure - 1.39 atm x 101 325 Pa/atm = 140 842 Pa

    V - volume - 75.0 x 10⁻³ m³

    n - number of moles

    R - universal gas constant - 8.314 Jmol⁻¹K⁻¹

    T - temperature in kelvin - 20 °C + 273 = 293 K

    substituting these values in the equation

    140 842 Pa x 75.0 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 293 K

    n = 4.34 mol

    molar mass of acetylene - 26 g/mol

    mass of acetylene present - 4.34 mol x 26 g/mol = 112.84 g

    mass of acetylene present - 112.84 g
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