A chemist requires 0.752 mol na2co3 for a reaction. how many grams does this correspond to?

79.70 grams First, calculate the molar mass of Na2CO3 by looking up the molar mass of the elements used in it. Sodium = 22.989769 Carbon = 12.0107 Oxygen = 15.999 Multiply each molar mass by the number of atoms used, and sum the results to get the molar mass 2 * 22.989769 + 12.0107 + 3 * 15.999 = 105.9872 Finally, multiply the molar mass by the number of moles you need. 0.752 * 105.9872 = 79.7024 grams