Based on the electron configuration of the two

atoms, predict the ratio of metal cationic (+) atom

to nonmetal anionic (-) atom in the compound.

Lithium 1s22s

Chlorine 1s22s22p 3s23p5

A. 1:1

B. 1:2

C. 2:1

D. 3:1

D. 3:1

A. 1 : 1

Explanation:

First off, it's important to identify the groups both elements belong to. This would enable us know the number of electrons that is needed to be lost or gained to reach it's octet configuration.

To identify the group from the electronic configuration, add the powers of the highest number present,

In Lithuium, the highest number is 2. It's power is 1. So it belongs to group 1. Hence it needs to lose it's one valence electron to reach it's octet state.

In Chlorine, the highest number is 3. The powers (3S and 3P) are 2 and 5. belongs to group 7. Hence it needs to gain one more electron to complete its octet configuration.

So what we have now is;

Li⁺ + Cl⁻

Since both charges cancels out, we have LiCl as the product compound. Hence the ratio of metal cationic (+) atom to nonmetal anionic (-) atom in the compound is 1 : 1

A

Explanation:

Cuz the when you pair Li and Cl, it becomes LiCl (it has 1:1 ratio)