Determine the dissociation constants for the following acids. Express the answers in proper scientific notation where appropriate

a. acid a has a pka of 6.0 what is its ka?

b. acid b has a pka of 8.60 whats its ka?

c. acid c has a pka of - 2.0 whats its ka?

How do you determine?

Ka is the acid dissociation constant. pKa is simply the - log of this constant.

Mathematically;

pKa = - log Ka

Ka = 10^-pKa

a. acid a has a pka of 6.0 what is its ka?

Ka = 10^-6 = 10⁻⁶

b. acid b has a pka of 8.60 whats its ka?

Ka = 10^-8.6 = 2.51e⁻⁹

c. acid c has a pka of - 2.0 whats its ka?

Ka = 10^ - (-2) = 10^2 = 100