Calculate the percent yield when 500 grams of carbon dioxide react with an excess of water to produce 640 grams of carbonic acid.

CO2 + H2O - --> H2CO3

Percent yield = 90.5%

Explanation:

Given dа ta:

Mass of carbon dioxide = 500 g

Mass of water = excess

Actual yield of carbonic acid = 640 g

Percent yield = ?

Solution:

Balanced chemical equation:

CO₂ + H₂O → H₂CO₃

Number of moles of carbon dioxide

Number of moles = Mass / molar mass

Number of moles = 500 g / 44 g/mol

Number of moles = 11.4 mol

Now we will compare the moles of H₂CO₃ with CO₂.

CO₂ : H₂CO₃

1 : 1

11.4 : 11.4

Mass of carbonic acid:

Mass = number of moles * molar mass

Mass = 11.4 mol * 62.03 g/mol

Mass = 707.14 g

Percent yield:

Percent yield = actual yield / theoretical yield * 100

Percent yield = 640 g / 707.14 g * 100

Percent yield = 90.5%