What is the experimental KHP concentration in a sample containing 10 mL of KHP solution (via volumetric pipet) that takes 12.39 mL of 0.04150 M NaOH to neutralize?

0.05142 M

Explanation:

Let's consider the neutralization reaction between KHP and NaOH.

KHC₈H₄O₄ + NaOH → H₂O + NaKC₈H₄O₄

12.39 mL of 0.04150 M NaOH were required for the neutralization. The moles that reacted are:

12.39 * 10⁻³ L * 0.04150 mol/L = 5.142 * 10⁻⁴ mol

The molar ratio of KHP to NaOH is 1:1. The moles of KHP that reacted are 5.142 * 10⁻⁴ mol.

5.142 * 10⁻⁴ moles of KHP were in 10 mL of solution. The concentration of the KHP solution is:

5.142 * 10⁻⁴ mol / 10 * 10⁻³ L = 0.05142 M