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11 June, 11:30

The molar heats of fusion and sublimation of molecular

iodineare 15.27 kJ/mol and 62.30 kJ/mol, respectively. Estimate the

molarheat of vaporization of liquid Iodine.

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Answers (1)
  1. 11 June, 13:42
    0
    47.03 KJ/mol

    Explanation:

    given:

    molar heat of fusion, Hfusion = 15.27 KJ/mol

    molar heat of sublimation, Hsublime = 62.30 KJ/mol

    molar heat of vaporisation, Hvaporise = ?

    Hsublime = Hfusion + Hvaporise

    Hvaporise = Hsublime - Hfusion

    Hence, the molar heat of vaporization of liquid iodine

    = 62.30 - 15.27 = 47.03 KJ/mol
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