Determine the oxidation number for nitrogenin

each of the following

a. NO2 1-

b. N2

c. NO2Cl

D. N2H4

2. Benzene is a common hydrocarbon, whic his widely used as a

solvent.

From another experiment, the molecular mass of benzene

wasdetermined to be 78.0 grams per mole. What is the

molecularformular for benzene?

1 (a) N = 3

(b) N = 0

(c) N = 5

(d) N = - 2

(2) Molecular formula for benzene is C6H6

Explanation:

1 (a) N02 1-

N + (2*-2) = - 1

N-4 = - 1

N = - 1+4 = 3

(b) N2

2 (N) = 0

N = 0/2 = 0

(c) NO2Cl

N + (2*-2) + (-1) = 0

N - 4 - 1 = 0

N - 5 = 0

N = 0+5 = 5

(d) N2H4

2 (N) + (4*1) = 0

2N + 4 = 0

2N = 0 - 4 = - 4

N = - 4/2 = - 2

(2) Molcular mass of benzene = 78g/mole = (6*12g of carbon) + (6*1g of hydrogen) = 72+6 = 78g/mole

Therefore, molecular formula for benzene is C6H6