How many grams of a solution that is 50% by weight NaOH

isrequired to make 1 Liter of 0.15M NaOH solution?

12 g

Explanation:

We want to prepare 1 L of a 0.15 M NaOH solution. The moles of NaOH required are:

0.15 mol/L * 1 L = 0.15 mol

The molar mass of NaOH is 40.00 g/mol. The mass corresponding to 0.15 mol is:

0.15 mol * (40.00 g/mol) = 6.0 g

The starting solution is 50% by weight. The mass of solution that contains 6.0 g of NaOH is:

6.0 g NaOH * (100 g solution/50 g NaOH) = 12 g solution