How many mL of 0.20M NaOH are required to neutralize 30 mL

of0.50M HCl?

75 mL

Explanation:

Let's consider the neutralization reaction between NaOH and HCl.

NaOH + HCl → NaCl + H₂O

The moles of HCl that reacted are:

0.030 L * 0.50 mol/L = 0.015 mol

The molar ratio of NaOH to HCl is 1:1. The moles of NaOH that reacted are 0.015 moles.

The volume of 0.20 M NaOH that contains 0.015 moles is:

0.015 mol / (0.20 mol/L) = 0.075 L = 75 mL