40 mL of 2.0 molar NaOH reacts with 8.0 mL of a

monoproticacid. What is the molarity of the acid?

10 M

Explanation:

In case of titration, the following formula can be used -

M₁V₁ = M₂V₂

where,

M₁ = concentration of acid,

V₁ = volume of acid,

M₂ = concentration of base,

V₂ = volume of base.

from, the question,

M₁ = ? M

V₁ = 8.0 mL

M₂ = 2.0 M

V₂ = 40 mL

Using the above formula, the molarity of acid, can be calculated as,

M₁V₁ = M₂V₂

M₁ * 8.0mL = 2.0 M * 40mL

M₁ = 10 M

Hence, the molarity of the acid = 10 M