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6 August, 16:14

A 0.907 mole sample of ideal gas at 12C occupies a volume of 4.25L. What is the pressure of gas?

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  1. 6 August, 18:20
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    4.99atm

    Explanation:

    PV=nRT

    P = nRT/V

    V = 4.25L

    T = 12 C = 285.15 kalvin

    n = 0.907 mol

    R = 0.082057 L⋅atm/mol⋅K

    P = (0.907) (0.082057) (285.15) / (4.25) = 4.9935 atm
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