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17 April, 02:49

Add the following thermochemical equations: (1) P4 (s) + 6Cl2 (g) = > 4PCl3 (g) ΔH = - 1148 kJ (2) 4PCl3 (g) + 4Cl2 (g) = > 4PCl5 (g) ΔH = -460 kJ (3) Overall equation = ? ΔHoverall = ? Select the correct ΔH for the overall process (equation 3)

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  1. 17 April, 06:39
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    the overall reaction is

    P4 (s) + 10Cl2 (g) = > 4PCl5 (g)

    and its ΔH is

    ΔH overall = (-1608 KJ)

    Explanation:

    given that

    P4 (s) + 6Cl2 (g) = > 4PCl3 (g), ΔH1 = - 1148 kJ

    4PCl3 (g) + 4Cl2 (g) = > 4PCl5 (g), ΔH2 = -460 kJ

    summing both equation gives

    P4 (s) + 6Cl2 (g) + 4PCl3 (g) + 4Cl2 (g) = > 4PCl3 (g) + 4PCl5 (g)

    but 4PCl3 (g) is in both sides, so is cancelled out

    P4 (s) + 6Cl2 (g) + 4Cl2 (g) = > 4PCl5 (g)

    summing the Cl2 (g)

    P4 (s) + 10Cl2 (g) = > 4PCl5 (g) → overall reaction

    (can be verified that the reaction is balanced)

    since we sum both equations the ΔH of the overall reaction is also the sum of the ΔH of the individual reactions.

    ΔH overall = ΔH1 + ΔH2 = (-1148 kJ) + (-460 kJ) = (-1608 KJ)
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