what is the volume in liters of 76 grams of fluorine (f2) at a temperature of 0 celcius and 101.3 kilopascals?

V = 44.83 L

Explanation:

Given dа ta:

Mass of fluorine = 76 g

Temperature = 0°C

Pressure = 101.3 Kpa

Volume of fluorine = ?

Solution:

Temperature = 0°C (0°C + 273 = 273 K)

Pressure = 101.3 Kpa (101.3 / 101 = 1 atm)

First of all we will calculate the number of moles.

Number of moles of F = Mass / molar mass

Number of moles = 76 g / 38 g/mol

Number of moles = 2 mol

Volume of fluorine:

Formula

PV = nRT

V = nRT / P

V = 2 mol * 0.0821 atm. L / mol. k * 273 k / 1 atm

V = 44.83 L. atm / 1 atm

V = 44.83 L