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3 June, 16:31

For the following reaction, 4.64 grams of oxygen gas are mixed with excess benzene (C6H6). The reaction yields 3.95 grams of carbon dioxide. benzene (C6H6) (l) oxygen (g) carbon dioxide (g) water (g) What is the theoretical yield of carbon dioxide

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  1. 3 June, 16:44
    0
    Theoretical yield for CO₂ is 5.10g

    Explanation:

    Reaction: 2C₆H₆ (l) + 15O₂ (g) → 12CO₂ (g) + 6H₂O (g)

    We convert the mass of oxygen to moles:

    4.64 g / 32 g/mol = 0.145 moles of O₂

    Let's find out the 100% yield reaction of CO₂ (theoretical yield)

    Ratio is 15:12. So let's make this rule of three:

    15 moles of O₂ can produce 12 moles of CO₂

    Therefore 0.145 moles of oxygen will produce (0.145. 12) / 15 = 0.116 moles

    We convert the moles to mass: 0.116 mol. 44 g / 1mol = 5.10 g
  2. 3 June, 18:43
    0
    The theoretical yield of carbon dioxdide = 5.11 grams

    Explanation:

    Step 1: Data given

    Mass of oxygen gas = 4.64 grams

    Molar mass of O2 = 32.0 g/mol

    The reaction yields 3.95 grams of carbon dioxide (CO2)

    Molar mass CO2 = 44.01 g/mol

    Step 2: The balanced equation

    2C6H6 + 15O2 → 12CO2 + 6H2O

    Step 3: Calculate moles oxygen

    Moles oxygen = mass oxygen / molar mass oxygen

    Moles oxygen = 4.64 grams / 32.0 g/mol

    Moles oxygen = 0.145 moles

    Step 4: Calculate moles of carbon dioxide (CO2)

    For 2 moles C6H6 we need 15 moles O2 to produce 12 moles CO2 and 6 moles H2O

    For 0.145 moles O2 we'll have 12/15 * 0.145 = 0.116 moles CO2

    Step 5: Calculate mass CO2

    Mass CO2 = moles CO2 * molar mass CO2

    Mass CO2 = 0.116 moles * 44.01 g/mol

    Mass CO2 = 5.11 grams

    The theoretical yield of carbon dioxdide = 5.11 grams
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